fai default install kernel is vmlinuz-2.6.18-6-486

[kegstand]

My fai server is running debian etch amd64 . I am booting i386
clients.  I do this because VirtualBox doesn't support 64 bit guests
yet, but that is not today's' problem.

I have this in my make-nfs-root config file:

# - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
# following lines should be read only for most of you

FAI_DEBOOTSTRAP_OPTS="--arch i386 --exclude=dhcp-client,info"

here is the pxe boot conf file that gets generated by fai-chroot:

#####################################################################
default fai-generated

label fai-generated
localboot 0
# generated by fai-chboot for host sata-test with IP 10.0.0.225
default fai-generated

label fai-generated
kernel vmlinuz-2.6.18-6-486
append initrd=initrd.img-2.6.18-6-486 ip=dhcp  root=/dev/nfs
nfsroot=/srv/fai/nfsroot boot=live  FAI_FLAGS=verbose,sshd,createvt
FAI_ACTION=install
#######################################################################




I would like to boot 2.6.18-6-686 by default.  How do I do that,
besides hand editing the file?
also I don't see the proper initrd and boot image in /srv/tftp/ for
pxe booting anyway, how would i get the proper one for 2.6.18-6-686 in
to there?

thanks.